I would like to get all rics of chain of chain 0#LCO++ in python

taya.mahendrarajah01

hi,

I would like to get all rics of chain of chain 0#LCO++ in python

in 0#LCO++ , you have other chain 0#LCOc1++,0#LCOc2++,0#LCOc3++ , …..

how can I get rics under each chains using a function from 0#LCO++?

ujjawal_khandelwal

Hi @taya.mahendrarajah01,
Thank you for your question! Below is one of the methods I could think of.

To get all the RICs from a chain of chains such as 0#LCO++, you can start by retrieving the first‑level constituents. In LSEG Data Library for Python, a chain is treated as just another instrument, so you can load it using ld.get_data().

Step 1 - Get the constituents of the main chain (0#LCO++):

Note: DSPLY_NAME field is real-time field. TR.* field would not help in this case.

import lseg.data as ld

import time

ld.open_session()

chain_1 = ld.get_data(

universe=["0#LCO++"],fields=["DSPLY_NAME']

)
first_level_rics = chain_1.Instrument.to_list()


print(first_level_rics)

Step 2 - Loop through each sub‑chain to get their constituents:

all_constituents = {}


for ric in first_level_rics:

    try:

        data = ld.get_data(universe=[ric], fields=["DSPLY_NAME"])

        all_constituents[ric] = data.Instrument.to_list()


        # Add delay (e.g., 0.5 seconds) to control throttling

        time.sleep(0.5)


    except Exception as e:

        print(f"Error reading {ric}: {e}")

        time.sleep(0.5)   # also delay between errors

This will collect all the RICs under each of the sub‑chains.

Note on errors:
You may notice that some chain RICs like 0#LCOc66++ return errors.
This usually means:

• The chain is empty
  
• The chain is deprecated
  
• Some other reason.

These situations require validation on the content side, so if a particular RIC consistently fails, you can raise a ticket with LSEG Support to check the chain definition as we are not the content experts.

Hope this helps. Please continue on this thread if you need help further.

Thank you :)